CCTV Storage for four 2MP IP CCTV cameras for 1 month
How to Calculate Storage for 4 Pieces of 2MP IP CCTV Cameras for One Month in Kenya
CCTV Storage for four 2MP IP CCTV cameras for 1 month. When setting up CCTV cameras for homes, businesses, or offices, storage is one of the most critical aspects to consider. The amount of storage required depends on factors such as resolution, compression, frame rate, and recording duration. In this guide, we will calculate the storage required for four 2-megapixel (2MP) IP cameras recording continuously for 30 days.

Factors Affecting Storage Calculation
- Camera Resolution: A 2MP camera typically records at 1920 × 1080 pixels (Full HD).
- Bitrate: The bitrate determines how much data the camera records per second. A 2MP IP camera usually has a bitrate of 2-4 Mbps depending on compression settings.
- Compression Technology: H.264, H.265, and H.265+ are commonly used compression formats. H.265+ offers the best storage optimization.
- Frame Rate: A typical CCTV camera records at 15 to 30 frames per second (FPS).
- Recording Type: Continuous recording (24/7) requires more storage than motion-based recording.
Storage Calculation Formula
To estimate the storage needed, we use the following formula:Storage (GB)=Bitrate (Mbps)×3600×24×Days8×1024\text{Storage (GB)} = \text{Bitrate (Mbps)} \times \frac{3600 \times 24 \times \text{Days}}{8 \times 1024}Storage (GB)=Bitrate (Mbps)×8×10243600×24×Days
Where:
- Bitrate is in Megabits per second (Mbps).
- 3600 is the number of seconds in an hour.
- 24 is the number of hours in a day.
- Days is the total recording period (30 days).
- 8 converts bits to bytes.
- 1024 converts MB to GB.
Step-by-Step Calculation
Assuming:
- Each 2MP camera records at 2 Mbps using H.265+ compression.
- 4 cameras recording continuously for 30 days.
Step 1: Calculate Storage for One Camera
Storage per camera=2×3600×24×308×1024\text{Storage per camera} = 2 \times \frac{3600 \times 24 \times 30}{8 \times 1024}Storage per camera=2×8×10243600×24×30 =2×25920008192= 2 \times \frac{2592000}{8192}=2×81922592000 =2×316.41= 2 \times 316.41=2×316.41 =632.82 GB= 632.82 \text{ GB}=632.82 GB
Step 2: Calculate Storage for 4 Cameras
Total Storage=632.82×4\text{Total Storage} = 632.82 \times 4Total Storage=632.82×4 =2531.28 GB= 2531.28 \text{ GB}=2531.28 GB =2.53 TB= 2.53 \text{ TB}=2.53 TB
Final Storage Requirement
For four 2MP IP CCTV cameras recording continuously for 30 days at 2 Mbps bitrate, you need approximately 2.53 TB of storage.
Adjusting for Higher Bitrate
If the cameras use 4 Mbps instead of 2 Mbps, the storage required would double to 5.06 TB.
Tools for Storage Calculation
If you want an easy way to estimate storage, you can use online CCTV storage calculators:
- Hikvision Storage Calculator: Hikvision Storage Calculator
- Dahua Storage Calculator: Dahua Calculator
- Western Digital Surveillance Storage Calculator: WD Storage Calculator
Conclusion
When setting up a CCTV system, always consider storage capacity to avoid recording loss. To optimize storage, use H.265+ compression, reduce frame rate, and enable motion detection recording instead of 24/7 continuous recording.
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